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-5=2x^2-4x+9
We move all terms to the left:
-5-(2x^2-4x+9)=0
We get rid of parentheses
-2x^2+4x-9-5=0
We add all the numbers together, and all the variables
-2x^2+4x-14=0
a = -2; b = 4; c = -14;
Δ = b2-4ac
Δ = 42-4·(-2)·(-14)
Δ = -96
Delta is less than zero, so there is no solution for the equation
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